Two thin conducting shells of radii $R$ and $3R$ are shown in the figure. The outer shell carries a charge $+ Q$ and the inner shell is neutral. The inner shell is earthed with the help of a switch $S$.
Diffcult
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Let $q$ be the charge attained by the inner shell.
As the inner shell is earthed so potential at any point on the surface of the shell is zero
i.e. $V=0=V_{\text {in}}+V_{\text {out}}=\frac{k q}{R}+\frac{k Q}{3 R}$
$\therefore q=-\frac{Q}{3}$
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