Variation of electrostatic potential along $x$-direction is shown in the graph. The correct statement about electric field is
A$x$ component at point $B$ is maximum
B$x $ component at point $A$ is towards positive $x$-axis.
C$x$ component at point $C$ is along negative $x-$ axis
D$x $ component at point $C$ is along positive $x$ -axis
Medium
Download our app for free and get started
D$x $ component at point $C$ is along positive $x$ -axis
d Electric field $E_{x}=-\frac{d V}{d x} .$ So for negative slope, field will be directed along positive $x$. Thus $x$ component at point $A$ is towards negative $x$ $-axis$ and $x$ component at point $C$ is along positive $x$ $-axis$ and at point $B, x$ $-component$ of field will be minimum.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Six metallic plates each with a surface area of one side $A$, are placed at a distance $d$ from each other. The alternate plates are connected to points $P$ and $Q$ as shown in figure. The capacitance of the system is
The linear charge density on a dielectric ring of radius $R$ varies with $\theta $ as $\lambda \, = \,{\lambda _0}\,\cos \,\,\theta /2,$ where $\lambda _0$ is constant. Find the potential at the centre $O$ of ring. [in volt]
Two charges of magnitude $+ q$ and $-\,3q$ are placed $100\,cm$ apart. The distance from $+ q$ between the charges where the electrostatic potential is zero is.......$cm$
A thin metallic partition of negligible thickness is inserted between two shaded metallic plates as shown. The remaining ends are then packed with insulating plates to form a container like structure.$2$ taps shown are opened at $t = 0$ and finally closed at $t = 5s$. Find capacitance of system between $A$ and $B$ after closing taps. (Assume liquid to be non conducting) Volumetric flow rates and dieletric constants of liquid are given.