\(P V=\frac{1}{3} m n V_{r m s}^{2}=\frac{2}{3} \times \frac{1}{2} m n v_{\text {rms }}^{2}=\frac{2}{3} k T\)
Boyle's law state that at constant temperature average \(K E\) is constant, So, \(v_{\text {rms }}\) Memains unchanged. If volume increases pressure of gas decreases.
i.e., \(P V=\) constant .
Charle's law state that if we allow the volume to change to maintain constant pressure the volume will increase with increasing temperature
\(\text { i.e., } V=K T\)
\(\therefore\) Option \((c)\) is correct.
$[k_B\, = 1 .4\times10^{-23}\,J/K;\, m_{He}\, = 7\times10^{-27}\,kg]$