\(f=6 \times 10^{14}\)
\(\lambda = \frac{C}{f} = \frac{{3 \times {{10}^8}}}{{6 \times {{10}^{14}}}} = 5000\,\,\mathop {\text{A}}\limits^o \)
Energy of photon \(\Rightarrow \frac{12375}{5000}=2.475\, \mathrm{eV}\)
From Einstein's equation
\(\mathrm{KE}_{\max }=\mathrm{E}-\phi\)
\(\mathrm{eV}_{\mathrm{s}}=\mathrm{E}-\phi\)
\(\mathrm{eV}_{\mathrm{s}}=2.475-2\)
\(\mathrm{eV}_{\mathrm{o}}=0.475\, \mathrm{eV}\)
\(\mathrm{V}_{\mathrm{o}}=0.48\, \mathrm{V}\)
${hc}=20 \times 10^{-26}\, {J}-{m}$, ઇલેક્ટ્રોનનું દળ $=9 \times 10^{-31} \,{kg}$