${{f'}}(x)\,\, = \,\,\frac{{\sin \,x}}{x}\,\,\,x\,\, > \,\,0\,\,\, $
$\Rightarrow \,\,{{f'}}(x)\,\, = \,\,0$
$\frac{{\sin \,x}}{x}\,\, = \,\,0$
જ્યારે $\,{\text{x}}\,\, = \,\,{\text{n}}\pi \,\,\, \Rightarrow \,\,{{f'}}{\text{(x)}}\,\, = \,\,\frac{{{\text{sin}}\,{\text{x}}}}{{\text{x}}}=0$ થાય.
\[ \Rightarrow \,\,{{f''}}(x)\,\, = \,\,\frac{{x\,\, \times \,\,\cos \,x\,\, - \,\,\sin \,x}}{{{x^2}}}\,\,\, = \,\,\,\frac{{x\,\cos \,x\,\, - \,\,\sin \,x}}{{{x^2}}}\]
$x = n\pi ; \pi $ ના બધા જ એકી સહગુણકો માટે, $ cosx $ ઋણ થાય અને શૂન્ય બને.
તેથી, તે $x = n\pi$ આગળ મહત્તમ થાય, $n $ એકી છે.
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