MCQ
What is the weight of oxygen required for the complete combustion of $2.8\, kg$ of ethylene ................ $\mathrm{kg}$
- A$2.8$
- ✓$9.6$
- C$6.4$
- D$96$
$28\,gm$ ${C_2}{H_4}$ requires $96\,gm$ oxygen
$\therefore $ $2.8 \times {10^3}$ $gm$ ${C_2}{H_4}$ requires =$\frac{{96}}{{28}} \times 2.8 \times {10^3}\,gm$ $ = 9.6 \times {10^3}\,gm$ = $9.6\,kg$.
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