When a force is applied on a wire of uniform cross-sectional area $3 \times {10^{ - 6}}\,{m^2}$ and length $4m$, the increase in length is $1\, mm.$ Energy stored in it will be $(Y = 2 \times {10^{11}}\,N/{m^2})$
  • A$6250\, J$
  • B$0.177 \,J$
  • C$0.075\, J$
  • D$0.150 \,J$
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