(The bulk modulus of rubber $=9.8 \times 10^{8}\, {Nm}^{-2}$ Density of sea water $=10^{3} {kgm}^{-3}$
$\left.{g}=9.8\, {m} / {s}^{2}\right)$
$-\frac{B \frac{\Delta V}{V}}{\rho g}=h$
$\frac{9.8 \times 10^{8} \times 0.5}{100 \times 10^{3} \times 9.8}=h$
$h=500$

