When heat energy of $1500\; Joules$, is supplied to a gas at constant pressure $2.1 \times {10^5}\;N/{m^2}$, there was an increase in its volume equal to $2.5 \times {10^{ - 3}}\;{m^3}$. The increase in internal energy of the gas in Joules is ...... $J$
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(c) According to FLOT
$\Delta Q = \Delta U + P(\Delta V)$==> $\Delta U = \Delta Q - P(\Delta V)$
$ = 1500 - (2.1 \times {10^5})(2.5 \times {10^{ - 3}})$$=975 \,Joule$
$\Delta Q = \Delta U + P(\Delta V)$==> $\Delta U = \Delta Q - P(\Delta V)$
$ = 1500 - (2.1 \times {10^5})(2.5 \times {10^{ - 3}})$$=975 \,Joule$
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