Within a spherical charge distribution of charge density $\rho \left( r \right)$, $N$ equipotential surfaces of potential ${V_0},{V_0} + \Delta V,{V_0} + 2\Delta V,$$.....{V_0} + N\Delta V\left( {\Delta V > 0} \right),$ are drawn and have increasing radii $r_0, r_1, r_2,......r_N$, respectively. If the difference in the radii of the surfaces is constant for all values of $V_0$ and $\Delta V$ then
JEE MAIN 2016, Diffcult
Download our app for free and get started
As we know electric field, $E = \frac{{ - dv}}{{dr}}$
$E=$ constant $\therefore $ $dv$ and $dr$ same
$ \Rightarrow \,\rho \propto \frac{1}{r}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Three isolated equal charges are placed at the three comers of an equilateral triangle as shown in figure. The statement which is true for net electric potential $V$ and net electric field intensity $E$ at the centre of the triangle is
Four plates of the same area of cross-section are joined as shown in the figure. The distance between each plate is $d$. The equivalent capacity across $A$ and $B$ will be
A capacitor of capacity ${C_1}$ is charged upto $V$ volt and then connected to an uncharged capacitor of capacity ${C_2}$. Then final potential difference across each will be
A paralle plate capacitor is made up of stair like structure with a palte area $A$ of each stair and that is connected with a wire of length $b$, as shown in the figure. The capacitance of the arrangement is $\frac{ x }{15} \frac{\varepsilon_{0} A }{ b }$. The value of $x$ is ............
A charge of $5\,C$ is given a displacement of $0.5\,m$. The work done in the process is $10\,J$. The potential difference between the two points will be.......$V$
A parallel plate capacitor with plates of area $1\,m^2$ each, are at a separation of $0.1\,m.$ If the electric field between the plates is $100\,N/C,$ the magnitude of charge on each plate
A parallel plate capacitor $\mathrm{C}$ with plates of unit area and separation $\mathrm{d}$ is filled with a liquid of dielectric constant $\mathrm{K}=2$. The level of liquid is $\frac{\mathrm{d}}{3}$ initially. Suppose the liquid level decreases at a constant speed $V,$ the time constant as a function of time $t$ is Figure: $Image$