MCQ
$\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1,$ તો $\frac{{dy}}{{dx}} = ...........$
- ✓$\frac{{{b^2}x}}{{{a^2}y}}$
- B$\frac{{{b^2}y}}{{{a^2}x}}$
- C$\frac{{{a^2}x}}{{{b^2}y}}$
- D$\frac{{{a^2}y}}{{{b^2}x}}$
$\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$
$\therefore \frac{2x}{a^2}-\frac{2y}{b^2}\frac{dy}{dx}=0$
$\therefore \frac{2x}{a^2}=\frac{2y}{b^2}\frac{dy}{dx}$
$\therefore \frac{2xb^2}{a^2 2y}=\frac{dy}{dx}$
$\therefore \frac{dy}{dx}=\frac{b^2x}{a^2y}$
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