Question
यदि ${(1 + i\sqrt 3 )^9} = a + ib,$ तो $b$ का मान है
${(1 + i\sqrt 3 )^9} = {(2{e^{i\pi /3}})^9} = {2^9}.{e^{i(3\pi )}}$
$ = {2^9}(\cos 3\pi + i\sin 3\pi ) = - {2^9}$
$a + ib = {(1 + i\sqrt 3 )^9} = - {2^9}$; $b = 0$
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