Young's moduli of the material of wires $A$ and $B$ are in the ratio of $1: 4$, while its area of cross sections are in the ratio of $1: 3$. If the same amount of load is applied to both the wires, the amount of elongation produced in the wires $A$ and $B$ will be in the ratio of
[Assume length of wires $A$ and $B$ are same]
A$36: 1$
B$12: 1$
C$1: 36$
D$1: 12$
JEE MAIN 2023, Medium
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B$12: 1$
b $\Delta L =\frac{ FL }{ AY }$
$\frac{\Delta L_{ A }}{\Delta L _{ B }}=\frac{ A _{ B }}{ A _{ A }} \frac{Y_{ B }}{Y_{ A }}=12$
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