Is always zero.
Explanation:
Net Electric force = FA + FB
= -qE + qE
= 0
Explanation:
Region AB shows the potential difference across capacitor C1 and region CD shows the potential difference across capacitor C2. Now, we can see from the graph that region AB is greater than region CD. Therefore, the potential difference across capacitor C1 is greater than that across capacitor C2.
$\because$ Capacitance, $\text{C}=\frac{\text{Q}}{\text{V}}$
$\therefore\text{C}_1<\text{C}_2$ (Q remains the same in series connection).
Increases.
Explanation:
Electric Potential Energy $=\text{q}\text{Dv}$
$=\text{q}(\text{v}_\text{f}-\text{v}_\text{i})$
If positive charge is shifted from a Low potential region to a High-Potential region, then electric Potential Energy increases.
Explanation:
When electron comes closer to the other stationary electron, its kinetic energy decreases because of repulsion between them. As per conservation of energy, the potential energy increases.
A diode valve can be used as a rectifier.
A triode valve can be used as a rectifier.
A triode valve can be used as an amplifier.
Explanation:
A diode valve and a triode valve allow current to flow only in one direction. Since a rectifier is a device that converts alternating current (bi-directional) into direct current (uni-directional), a diode valve and a triode valve can be used as rectifiers. A triode valve can control its output in proportion to the input signal. That is, it can act as an amplifier, whereas a diode valve cannot control its output in proportion to the input signal. So, it cannot be use as an amplifier.
Explanation:
The thin metal plate inserted between the plates of a parallel-plate capacitor of capacitance C connects the two plates of the capacitor; hence, the distance d between the plates of the capacitor reduces to zero. It can be observed that the charges on the plates begin to overlap each other via the metallic plate and hence begin to conduct continuously.
Mathematically,
$\text{C}=\frac{\in_0\text{A}}{\text{d}}$
In this case, d = 0.
$\therefore\text{C}=\infty$
Explanation:
When a dielectric material is inserted between the plates of the parallel plate capacitor, the capacitance of the capacitor increases with a factor of K. That is C = KC0.
Explanation:
The capacitance of a capacitor is given by:
$\text{C}=\frac{\in_0\text{A}}{\text{d}}$
Here, A is the area of the plates of the capacitor and d is the distance between the plates.
So, we can clearly see that the capacitance of a capacitor does depend on the size and shape of the plates and the separation between the plates; it does not depend on the charges on the plates.
Explanation:
The required voltage is 1000v and the capacitors are parallel as 250v.
So number of capacitors required will be 4 i.e250 × 4 = 1000 in series.
Now example of four capacitor in series will be equal 2μf (micro farade) but the equivalent capacitance required is given as 16μf so there must be 8 series of parallel arrange capacitors each of capacitor 2 micro farad hence total number of capacitor = 4 × 8 = 32
Explanation:
The plate current varies directly with the plate voltage. Therefore, if the plate voltage is zero, the plate current is also zero. Due to the same reason, if the plate voltage is negative, the plate current will be zero. Now, if the plate is slightly positive, then it may be the reason that the plate voltage is not able to reduce the effect of space charge. Hence, the current may be zero. Now, as the temperature of the filament is low, it will not be able to emit electrons and the resulting plate current will be zero. Hence, all the options are possible.
Explanation:
Electrical potential is a type of potential energy, and refers to the energy that could be released if electric current is allowed to flow.
Explanation:
Work done by the electrostatic force is independent of the path followed by it, and it depends only on the initial and final positions. For example, work done in moving a unit positive charge in a closed loop of an electric field is zero. So,electrostatic force is a conservative force.
Explanation:
The electric potential is the electric potential energy per unit charge.
Explanation:
Electrostatic shielding is a phenomenon seen when a Faraday cage is used to block the effects of an electric field.
Explanation:
The charge induced on the plates of a capacitor is independent of the area of the plates.
$\therefore$ Q+ = Q-
Explanation:
Equivalent capacitance of each pair of capacitance in series$=\frac{1\times1}{1+1}\text{F}=0.5\text{F}$
The two series combination are connected in parallel. Hence the net capacitance becomes 0.5F + 0.5F = 1F
Explanation:
The resultant capacitor when capacitors are joined in series is the reciprocal of the sum of the reciprocals of the indivisual capacitors.
Explanation:
A molecule in which the centre of mass of positive and negative charges does not collide with each other is called a polar molecule. They have a permanent dipole moment. They have unsymmetrical shapes.
The positive charge will experience an electrostatic force whose direction will be along the direction of electric field.
In other words, positive charge will move from high electrostatic potential to low electrostatic potential.
Work will be done by electric filed on the charge and the electric potential energy of the charge will decrease.
Explanation:
If a point charge is situated at infinity, the electric field lines coming out of it will be in the form of parallel straight lines. As we know that field lines cut the equipotential surfaces orthogonally, therefore the equipotential surfaces must be plane surfaces. They can be considered the surface of a sphere of infinite radius.
Explanation:
The volt is a measure of electric potential. One volt is defined as the difference in electric potential between two points of a conducting wire when an electric current of one ampere dissipates one watt of power between those points. It is also equal to the potential difference between two parallel, infinite planes spaced 1 meter apart that create an electric field of 1 newton per coulomb. Additionally, it is the potential difference between two points that will impart one joule of energy per coulomb of charge that passes through it. It can be expressed in terms of SI base units (m, kg, s, and A)
$1\text{volte}=\frac{1\text{joule}}{\text{Coulomb}}$
Explanation:
When we insert a dielectric between the plates of a capacitor, induced charges of opposite polarity appear on the face of the dielectric. They build an electric field inside the dielectric, directed opposite to the original field of the capacitor.
Thus, the net effect is a reduced electric field.
Also, as the potential is proportional to the field, the potential decreases and so does the stored energy U, which is given by
$\text{U}=\frac{\text{qV}}{2}$
Thus, only the charge on the capacitor remains unchanged, as the charge is conserved in an isolated system.
Explanation:
Oil between the plates of the capacitor acts as a dielectric. We know that the electric field decreases by a factor of $\frac{1}{\text{K}}$ of the original field when we insert a dielectric between the plates of a capacitor (K is the dielectric constant of the dielectric). So, if the oil is pumped out, the electric field between the plates will increase, as the dielectric has been removed.
Explanation:
The relation between the induced charge Q' and the charge on the capacitor Q is given by:
$\text{Q}'=\text{Q}\Big(1-\frac{1}{\text{K}}\Big)$
Here, K is the dielectric constant that is always greater than or equal to 1.
So, we can see that for K > 1, Q' will always be less than Q.
Explanation:
The maximum energy that can be desirably stored in a capacitor is depends on the maximum electric field that the dielectric can withstand without breaking down. Therefore, capacitors of the same type have about the same maximum energy density, i.e. joules of energy per cubic meter.
Explanation:
As the battery remains connected across the capacitor, so the potential difference remains constant at V0 even after the introduction of the dielectric slab. In this way, dielectric has an effect on potential difference.
Explanation:
The potential is seen to be a constant on a sphere at all points.
Explanation:
Electric field at any point is equal to the negative of the potential gradient. But inside a conductor, the electric field is zero. Hence, the electric potential is constant throughout the volume of a conductor and has the same value on its surface. Thus the surface of a conductor is equipotential.
Explanation:
When the dielectric slab is introduced between the plates, the induced surface charge on the dielectric reduces the electric field.
The reduction in the electric field results in a decrease in potential difference.
$\text{V}=\text{Ed}=\frac{\text{E}_0\text{d}}{\text{k}}=\frac{\text{V}_0}{\text{k}}$
Explanation:
Given that some charge is given to a conductor then the whole charge is distributed over its surface only. Inside of conductor, electric field is zero whereas potential is same as on the surface. Hence, throughout the conductor, potential is same i.e, the whole conductor is equipotential.
Explanation:
Every condenser is made with two plates. The charge on one plate is +Q and other is −Q.
Thus total charge of condenser is Qt = +Q - Q = 0