Explanation:
We know that electric field lines cross the equipotential surfaces perpendicularly. Electric field lines are generated radially from a positive point charge. Therefore, for holding both the conditions, the equipotential surfaces must be spherical.
Explanation:
Work done = potential × charge by definition. We know that the potential of a point is the amount of work done to bring a unit charge from infinity to a certain point. Therefore, work done W = q × V = 4 × 10-3 × 200J = 0.8J. The work done is positive in this case.
Explanation:
CO2 is a molecule in which the centre of mass of positive and negative charges collide with each other and is called a non-polar molecule. They normally have zero dipole moment. They have symmetrical shapes.
Explanation:
Since the potential at point A is equal to the potential at point B, no current will flow along arm AB. Hence, the capacitor on arm AB will not contribute to the circuit. Also, because the remaining two capacitors are connected in parallel, the net capacitance of the circuit is given by
Ceq = C + C = 2C
Explanation:
As no cell is connected to the capacitor, the charge will remain constant.
Explanation:
Work done is given difference in potentials. In an equipotential surface, all points will have same potential. Thus work done is zero
Explanation:
The force between the plates is given by
$\text{F}=\frac{\text{q}^2}{2\in_0\text{A}}$
Since the capacitor is isolated, the charge on the plates remains constant.
We know that the charge is conserved in an isolated system.
Thus, the force acting between the plates remains unchanged.
Explanation:
$\text{E}=\text{E}_0\hat{\text{i}}$ (Given)
(Potential at A):-
$\text{V}_\text{A}=\big(\text{E}_0\hat{\text{i}}\times\text{a}\hat{\text{i}}\big)=\text{E}_09$
(Potential atB):-
$\text{V}_\text{B}=\big(\text{E}_0\hat{\text{i}}\times\text{a}\hat{\text{i}}\big)=0$
(Potential at C):-
$\text{V}_\text{C}=\big(\text{E}_0\hat{\text{i}}\times(-\text{a})\text{i}\big)=\text{E}_0\text{a}$
(Potential atD):-
$\text{V}_\text{D}=(\text{E}_0\hat{\text{i}}\times(-\text{a})\hat{\text{j}})=0$
Explanation:
In the outer regions above the upper plate and below the lower plate, the electric fields due to the two charged plates cancel out. Hence, the net electric field in the outer regions above the plate and below the lower plate is zero.
Explanation:
The phenomenon of making a region free from any electric field is called electrostatic shielding. It is based on the fact that the electric field vanishes inside the cavity of a hollow conductor.
Explanation:
NH3 is a molecule in which the centre of mass of positive and negative charges does not collide with each other and is called a polar molecule. They have a permanent dipole moment. They have unsymmetrical shapes.
Explanation:
To move a body against some force, work is to be done on the body. In this case, an external force is to be applied on the body to move it i.e. an external work is to be done. As we are moving the body against the Coulomb’s force, hence no work is done on the body by the electric field.
Explanation:
Given that point A is at lower electric potential than point B. The electron between them on line joining will move.
We have to find where this electron moves.
Since we know that electric currents move from a higher potential or a lower potential. Also, electrons move in the direction opposite to electric current. So the electron on the line joining two points A and B will move from lower to higher potential i.e, it will move towards B.
The potential of a body is due to charge of the body and due to the charge of surrounding. If there are no charges anywhere else outside, then the potential of the body will be due to its own charge. If there is a cavity inside a conducting body, then charge can be placed inside the body. Hence there must be charges on its surface or inside itself.
Hence option (a) is correct. The charge resides on the outer surface of a closed charged conductor. Hence there cannot be any charge in the body of the conductor.
Hence option (b) is correct.
Explanation:
An electric potential (also called the electric field potential or the electrostatic potential) is the amount of electric potential energy that a unitary point electric charge would have if located at any point of space, and is equal to the work done by an electric field in carrying a unit positive charge from infinity to that point.
This value can be calculated in either a static (time-invariant) or a dynamic (varying with time) electric field at a specific time in units of joules per coulomb, or volts (V). The electric potential at infinity is assumed to be zero.
Explanation:
If the anode is given a negative potential relative to the cathode, the electrons are pushed back to the cathode. Hence, no current will flow through the diode.
Explanation:
Positive charges move from higher to lower potential whereas negative charges move from lower to higher potential. Hence, A is false. Electric potential does not have direction and is a scalar quantity.
Explanation:
For IMAGE 01 AND 02:
[Loops AXBY forms wheat stone bridge ]
So, effective capacitance will be for the bridge C
In IMAGE 03 the parallel combination
C′ = C + C = 2C
Explanation:
Dielectric constant is the factor by which the capacitance increases from its value in air when a dielectric is introduced between the plates.
Mica, among the materials mentioned above, is a dielectric material and hence to be used to increase the capacity.
Explanation:
The magnitude of electric field is given as the change in magnitude of potential per unit displacement as
Explanation:
The potential difference between any two points on an equipotential surface is zero.
Work done = Test charge x potential difference(0)
Explanation:
Potential at surface of a sphere of radius r is V = kQ/ r
As identical sphere so r is same for both, Thus V will depend on charge Q.
So when Q is more, potential will be more.
Since −15 C is more than −16 C, so −15 C sphere will have higher potential.
Explanation:
The effective capacitance of a capacitor is increased when the capacitors are connected in parallel. When the capacitors are connected in parallel, the equivalent capacitance is given by:
Cp = C1 + C2 + C3 +…….
When the capacitors are connected in parallel, the potential difference across each capacitor is the same.
Explanation:
In conductors, charges are equally distributed over the surface of the conductor. Therefore the potential throughout the surface is the same, i.e. equipotential. The electric field is a vector quantity and the field lines cut the equipotential surfaces at 90 degrees. The field lines due to a point charge are radial.
Explanation:
Net electrostatic field is zero in the interior of a conductor. When a conductor is placed in an electric field, its free electrons begin to move in the opposite direction. Negative charges are induced on the left end and positive charges on the right end of the conductor. The process continues until the electric field set up by induced charges becomes equal and opposite the external field.
Explanation:
As the capacitor is charged by using cell so potential as well as filed between the plates become constant.
For removing dielectric the capacitance becomes C/ k. Thus capacitance decreases by a factor of k.
Explanation:
Equipotential surface
→ P.D difference between two points on the surface is zero always since potential is same everywhere in equipotential surface.
→ The EF is always perpendicular to the surface because there is no potential gradient along any direction parallel to the surface P so no EF parallel to the surface
→ Equipotential surface can have any shape not just sphere.
→ No work is done in moving a charge along the surface, because potential difference is zero.
Explanation:
After switch S is opened, as the Capacitor A is connected across the battery, its potential difference is fixed at steady state (i.e., when capacitor is fully charged).
Capacitor B is isolated, so its charge gets fixed. But as we insert the dielectric, its capacitance changes, thus its potential difference also changes.
Explanation:
Angular momentum about the hinge point of the ball will be max at point. mV will be max at closer point because law of conservation says that the swinging energy will be gathered when it will be at lowest point. The potential energy is maximum.
Explanation:
A dipole contains two equal and opposite charge. So total charge inside the sphere will be zero.
By Gauss's law, the flux across a surface is depends on the charge inside the surface. As total charge is zero inside the sphere so the flux through the sphere will be zero.
As the electric field is resultant effect due to all charges so there will be field exists on the surface.
As the sphere contains two equal and opposite charges so there may be exists equipotential surface in the sphere.
Equipotential surfaces are closer in regions of large electric fields because electric field intensity is inversely proportional to the separation between equipotential surfaces.
As the electric field intensities is large near sharp edges of a charged conductor or near the regions of large charge densities. Therefore, numbers of equipotential surfaces are closer to such places or in other words they are more crowded.
Explanation:
1 electron volt is the amount of work done if an electron is passed through a potential difference of 1V. Therefore the work done = 1V × charge of an electron = 1.602 × 10-19 J. But it is a small quantity and hence we use kilo electron volt and mega electron volt in practical.
Explanation:
In a parallel combination of capacitors, the potential difference across the capacitors remain the same, as the right-hand-side plates and the left-hand-side plates of both the capacitors are connected to the same terminals of the battery. Therefore, the potential remains the same, that is, V.
For the parallel combination of capacitors, the capacitance is given by
Ceq = C1 + C2
Here,
C1 = C2 = C
$\therefore$ Ceq = 2C
Explanation:
The net displacement round one complete circle is 0.