MCQ 11 Mark
The factors of $m^2 - 256$ are:
- A
$(m + 4)^2$
- B
$(m - 4)^2$
- C
$(m - 4) (m + 4)$
- ✓
Answer$m^4 = (m^2)^2\ \ and\ \ 256 = (16)^2$
$m^4 - 256 = (m^2)^2 - (16)^2 = (m^2 - 16) (m^2 + 16)$
$m^2 - 16 = m^2 - 4^2 = (m - 4) (m + 4)$
$m^4 - 256 = (m - 4) (m + 4) (m^2 + 16)$
View full question & answer→MCQ 21 Mark
The factors of $49p^2 - 36$ are:
- ✓
$(7p - 6) (7p + 6)$
- B
$(7p + 6)^2$
- C
$(7p - 6)^2$
- D
AnswerCorrect option: A. $(7p - 6) (7p + 6)$
a. $(7p - 6) (7p + 6)$
Solution:
$= 49p^2 - 36 = (7p)^2 – (6)^2$
$= (7p - 6) (7p + 6)$
View full question & answer→MCQ 31 Mark
The factorisation of $y^2 - 7y + 12$ is:
- A
$(y + 3) (y + 4)$
- B
$(y + 3) (y - 4)$
- C
$(y - 3) (y + 4)$
- ✓
$(y - 3) (y - 4)$
AnswerCorrect option: D. $(y - 3) (y - 4)$
$= y^2 - 7y + 12$
$= y^2 - 3y - 4y + 12$
$= y(y - 3) - 4(y - 3)$
$= (y - 3) (y - 4)$
View full question & answer→MCQ 41 Mark
The factorisation of $x^2 + 8x + 16$ is:
- A
$(x + 2)^2$
- ✓
$(x + 4)^2$
- C
$(x - 2)^2$
- D
$(x - A)^2$
AnswerCorrect option: B. $(x + 4)^2$
$= x^2 + 8x + 16$
$= (x)^2 + 2 (x) (4) + (4)^2$
$= (x + 4)^2$
View full question & answer→MCQ 51 Mark
The factors of $3m^2 + 9m + 6$ are:
- A
$(m + 1) (m + 2)$
- ✓
$3(m + 1) (m + 2)$
- C
$6(m + 1) (m + 2)$
- D
$9(m + 1) (m + 2)$
AnswerCorrect option: B. $3(m + 1) (m + 2)$
B. $3(m + 1) (m + 2)$
Solution:
$= 3m^2 + 9m + 6 = 3(m^2 + 3m + 2)$
$= 3 (m^2 + m + 2m + 2)$
$= 3m(m + 1) + 2( m + 1)$
$= 3(m + 1) (m + 2)$
View full question & answer→MCQ 61 Mark
The factors of $6xy - 4y + 6 - 9x$ are:
- A
$(3x + 2) (2y + 3)$
- B
$(3x - 2) (2y + 3)$
- C
$(3x - +2) (2y - 3)$
- ✓
$(3x - 2) (2y - 3)$
AnswerCorrect option: D. $(3x - 2) (2y - 3)$
$= 6xy - 4y + 6 - 9x$
$= 6xy - 4y - 9x + 6$
$= 2y(3x - 2) - 3(3x - 2)$
$= (3x - 2) (2y - 3)$
View full question & answer→MCQ 71 Mark
The common factor $12a$ and $30$ is:
Answer$12a = 2 \times 2 \times 3 \times a$
$30 = 2 \times 3 \times 5$
View full question & answer→MCQ 81 Mark
Solve: $-20(x)^4 \div 10(x)^2$
- A
$\frac{1}{2\text{x}}$
- B
$\text{x}$
- C
$\frac{1}{2}$
- ✓
$-2\text{x}^2$
AnswerCorrect option: D. $-2\text{x}^2$
D. $-2\text{x}^2$
View full question & answer→MCQ 91 Mark
If $(x^2 + 3x + 5) (x^2 - 3x + 5) = m^2 - n^2,$ what is the value of $m\ ?$
- A
$x^2 - 3x$
- B
$3x$
- ✓
$x^2 + 5$
- D
$x^2 + 3x$
AnswerCorrect option: C. $x^2 + 5$
C. $x^2 + 5$
View full question & answer→MCQ 101 Mark
The value of $\frac{0.73\times0.73\times-0.27\times0.27}{0.73-0.27}$ is:
AnswerValue $=\frac{(0.73+0.27)(0.73-0.27)}{0.73-0.27}=1$
View full question & answer→MCQ 111 Mark
Divide $44(a^2 - 5a^3 - 50a^2)$ by $11a(a - 10)$
- A
$4a(a - 10)$
- ✓
$4a(a + 5)$
- C
$4a$
- D
$(a + 5) (a - 10)$
AnswerCorrect option: B. $4a(a + 5)$
B. $4a(a + 5)$
Solution:
Write the division as a fraction
$\Rightarrow\frac{44(\text{a}^4-5\text{a}^3-50\text{a}^2)}{11\text{a}(\text{a}-10)}$
Find the factors of the numerator,
$\Rightarrow\frac{11\times4\text{a}^2(\text{a}^2-5\text{a}-50)}{11\text{a}(\text{a}-10)}$
$\Rightarrow\frac{11\times4\text{a}^2(\text{a}^2-10\text{a}+5\text{a}-50)}{11\text{a}(\text{a}-10)}$
$\Rightarrow\frac{11\times4\text{a}^2(\text{a}(\text{a}-10)+5(\text{a}-10))}{11\text{a}(\text{a}-10)}$
$\Rightarrow\frac{11\times4\text{a}^2(\text{a}+5)(\text{a}-10)}{11\text{a}(\text{a}-10)}$
Cancel the common factors from the numerator and denominator.
$\Rightarrow4(\text{a}+5)$
View full question & answer→MCQ 121 Mark
The factors of $x^2 + xy - 2xz - 2yz$ are:
- A
$(x - y)(x + 2z)$
- B
$(x + y)(x + 2z)$
- C
$(x + y)(x + 2z)$
- ✓
$(x + y)(x - 2z)$
AnswerCorrect option: D. $(x + y)(x - 2z)$
D. $(x + y)(x - 2z)$
View full question & answer→MCQ 131 Mark
Factorise: $x^2 + xy + 8x + 8y$
- ✓
$(x + 8) (x + y)$
- B
$(x + y)$
- C
$(x + 8)$
- D
$(x + 9) (x - y)$
AnswerCorrect option: A. $(x + 8) (x + y)$
A. $(x + 8) (x + y)$
View full question & answer→MCQ 141 Mark
The factorisation of $6 - x - 2x^2$ is:
- ✓
$(2 + x) (3 - 2x)$
- B
$(2 + x) (3 + 2x)$
- C
$(2 - x) (3 - 2x)$
- D
$(2 - x) (3 + 2x)$
AnswerCorrect option: A. $(2 + x) (3 - 2x)$
A. $(2 + x) (3 - 2x)$
Solution:
$= 6 - x - 2x^2$
$= 6 + 3x - 4x - 2x^2$
$= 3(2 + x) - 2x (2 + x)$
$= (2 + x) (3 - 2x)$
View full question & answer→MCQ 151 Mark
Factorize Completely $x^4 - 625$
AnswerCorrect option: A. $(x \div 5) (x - 5) (x^2 \div 25)$
A. $(x \div 5) (x - 5) (x^2 \div 25)$
Solution:
$x^4 - 625 = (x^2)^2 - (25)^2$
Apply the identity, $a^2 - b^2 = (a + b) (a - b)$
$\Rightarrow (x^2 + 25) (x^2 - 25)$
Factorize $(x^2 - 25)$ using the same identity.
$\Rightarrow (x^2 + 25) (x)^2 - (5)^2$
$\Rightarrow (x^2 + 25) (x + 5) (x - 5)$
View full question & answer→MCQ 161 Mark
The factorisation of $49p^2 - 36$ is:
- ✓
$(7p + 6) (7p - 6)$
- B
$(6p + 7) (6p - 7)$
- C
$(7p + 6)^2$
- D
$(7p - 6)^2$
AnswerCorrect option: A. $(7p + 6) (7p - 6)$
A. $(7p + 6) (7p - 6)$
Solution:
$= 49p^2 - 36$
$= (7p)^2 - (6)^2$
$= (7p - 6) (7p + 6)$
View full question & answer→MCQ 171 Mark
One factor od $a^2 - c^2 + b^2$
- A
$(a + b + c)$
- B
$(a + b - c)$
- ✓
$(a - b + c)$
- D
AnswerCorrect option: C. $(a - b + c)$
C. $(a - b + c)$
View full question & answer→MCQ 181 Mark
Which of the following is quotient obtained on dividing $(x^2 - b)\ (x - a)$ by $-(x - a)\ ?$
- A
$(\text{x}^2 – \text{b})$
- B
$\frac{-(\text{x}^2 – \text{b})}{(\text{x}-\text{a})}$
- ✓
$-(\text{x}^2 – \text{b})$
- D
$-(\text{x}+\text{a})$
AnswerCorrect option: C. $-(\text{x}^2 – \text{b})$
C. $-(\text{x}^2 – \text{b})$
Solution:
$(\text{x}^2-\text{b})(\text{x}-\text{a})$ By $-(\text{x}-\text{a})$
$\frac{(\text{x}^2-\text{b})(\text{x}-\text{a})}{-\text{x}-\text{a}}=\frac{\text{x}^2-\text{b}}{-(\text{x}-\text{a})}$
$=(\text{x}^2-\text{b)}$
View full question & answer→MCQ 191 Mark
The factors of $1 - p^3$ are:
- A
$(1 + p)(1 + p^2)$
- ✓
$(1- p)(1 + p + p^2)$
- C
$(1 + p)(1 - p - p^2)$
- D
$(1 + p)(1 - p^2)$
AnswerCorrect option: B. $(1- p)(1 + p + p^2)$
B. $(1- p)(1 + p + p^2)$
View full question & answer→MCQ 201 Mark
The factors of $x^2 + xy + 8x + 8y$ are:
- ✓
$(x +y) (x + 8)$
- B
$(2x + y) (x + 8)$
- C
$(x + 2y) (x + 8)$
- D
$(x + y) (2x + 8)$
AnswerCorrect option: A. $(x +y) (x + 8)$
A. $(x +y) (x + 8)$
Solution:
$= x^2 + xy + 8x + 8y$
$= x(x + y) + 8(x + y)$
$=(x + y) (x + 8)$
View full question & answer→MCQ 211 Mark
Tick $(\checkmark)$ the correct answer:
$x^3 - 144x = ?$
- A
$x(x - 12)^2$
- B
$x(x + 12)^2$
- ✓
$x(x - 12)(x + 12)$
- D
AnswerCorrect option: C. $x(x - 12)(x + 12)$
C. $x(x - 12)(x + 12)$
Solution:
$x^3 - 144x$
$= x(x^2 - 144)$
$= x{(x)^2 - (12)^2}$
$= x(x - 12)(x + 12)$
View full question & answer→MCQ 221 Mark
Substitute $a = -3$ in $a^2 + 7a + 5$ and figure out it equals how much.
AnswerB. $-7$
Solution:
Substitute $a = -3$ in $a^2 + 7a + 5$
$\Rightarrow (-3)^2 + 7(-3) +5$
$\Rightarrow 9 - 21 + 5$
$\Rightarrow 9 - 16$
$\Rightarrow -7$
View full question & answer→MCQ 231 Mark
The common factor of $72x^3y^4z^4, 120z^2d^4x^4$ and $96y^3z^4d^4$ is:
- A
$96z^3$
- B
$120z^3$
- C
$72z^3$
- ✓
$24z^2$
AnswerCorrect option: D. $24z^2$
D. $24z^2$
Solution:
$72x^3y^4z^4 = 2 \times 2 \times 2 \times 3 \times 3 \times x \times x \times x \times y \times y \times y \times y \times z \times z \times z \times z$
$120z^2d^4x^4 = 2 \times 2 \times 2 \times 3 \times 5 \times z \times z \times d \times d \times d \times d \times x \times x \times x \times x$
$96y^3z^4d^4 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times y \times y \times z \times z \times z \times z \times d \times d \times d \times d$
View full question & answer→MCQ 241 Mark
Tick $(\checkmark)$ the correct answer:
$x^2 - xz + xy - yz =\ ?$
- A
$(x - y)(x + z)$
- B
$(x - y)(x - z)$
- ✓
$(x + y)(x - z)$
- D
$(x - y)(z - x)$
AnswerCorrect option: C. $(x + y)(x - z)$
C. $(x + y)(x - z)$
Solution:
$x^2- xz + xy - yz$
$= x(x - z) + y(x - z)$
$= (x + y) (x - z)$
View full question & answer→MCQ 251 Mark
The factorisation of $12a^2b+15ab^2$ gives:
- A
$3ab(4ab + 5)$
- ✓
$3ab(4a + 5b)$
- C
$3a(4a + 5b)$
- D
$3b(4a + 5b)$
AnswerCorrect option: B. $3ab(4a + 5b)$
B. $3 a b(4 a+5 b)$
Solution:
$12 a^2 b+15 a b^2 $
$12 a^2 b=3 \times 4 \times a \times a \times b $
$15 a b^2=3 \times 5 \times a \times b \times b$
The common factors are 3ab.
$12 a^2 b+15 a b^2=3 a b(4 a+5 b)$
View full question & answer→MCQ 261 Mark
The factorisation of $8x + 4y$ is:
- ✓
$4(2x + y)$
- B
$8(x + 4y)$
- C
$4(2x + 4y)$
- D
$8(x + y)$
AnswerCorrect option: A. $4(2x + y)$
$4(2x + y)$
View full question & answer→MCQ 271 Mark
Which of the following are the factors of $a^2 + ab + bc + ca,$
- A
$(b + c) (c + a)$
- ✓
$(a + b) (a + c)$
- C
$a (a + b + c)$
- D
$(a + b) (b + c)$
AnswerCorrect option: B. $(a + b) (a + c)$
B. $(a + b) (a + c)$
Solution:
$= a^2 + ab + bc + ca$
$= a (a + b) + c (b + a)$
$= a (a + b) + c (a + b)$
$= (a + b) (a + c)$
Therefore, the factors of $a^2 + ab + bc + ca$ are $(a + b) (a + c).$
View full question & answer→MCQ 281 Mark
If $(x^2 + 3x + 5)(x^2 - 3x + 5) = m^2 - n^2,$ then $m =$
- ✓
$x^2 + 5$
- B
$x^2 - 3x$
- C
$3x$
- D
AnswerCorrect option: A. $x^2 + 5$
A. $x^2 + 5$
View full question & answer→MCQ 291 Mark
Tick $(\checkmark)$ the correct answer:
$2x^2 + 5x + 3 = \ ?$
- A
$(x + 3)(2x + 1)$
- ✓
$(x + 1)(2x + 3)$
- C
$(2x + 5)(x − 3)$
- D
AnswerCorrect option: B. $(x + 1)(2x + 3)$
B. $(x + 1)(2x + 3)$
Solution:
$2x^2+ 5x + 3$
$= 2x^2+ 2x + 3x + 3$
$= 2x(x + 1) + 3(x + 1)$
$= (2x + 3) (x + 1)$
View full question & answer→MCQ 301 Mark
Area of a quadrilateral $ABCD$ is $20cm^2$ and perpendiculars on $BD$ from opposite vertices are $1cm$ and $1.5cm.$ The length of $BD$ is:
- A
$4cm$
- B
$15cm$
- ✓
$16cm$
- D
$18cm$
AnswerCorrect option: C. $16cm$
Area of the given quadrilateral $=\frac{1}2{}$ (sum of altitudes) × Corresponding diagonal
$\Rightarrow20=\frac{1}{2}(1+1.5)\times\text{BD}$ [given]
$\Rightarrow\frac{1}2{}\times2.5\times\text{BD}=20\text{cm}^2$
$\Rightarrow\text{BD}=20\times\frac{2}{2.5}=\frac{40}{2.5}=16\text{cm}$
View full question & answer→MCQ 311 Mark
One of the factors of $a^3(b - c)^3+ b^3(c - a)^3+ c^3(a - b)$ is:
- ✓
$c - a$
- B
$b - c$
- C
$a - c$
- D
AnswerCorrect option: A. $c - a$
View full question & answer→MCQ 321 Mark
The value of $0.645 \times 0.645 + 2 × 0.645 \times 0.355 + 0.355 \times 0.355$ is:
AnswerA. $1$
Solution:
Value $= (0.645 + 0.355)^2 = (1)^2 = 1$
View full question & answer→MCQ 331 Mark
Divide $96pqr(3p - 12) (5q - 30)$ by $144(p - 4) (q - 6)$
- A
$5pqr$
- B
$pqr$
- C
$\frac{2}{3}\text{pqr}$
- ✓
$10pqr$
AnswerCorrect option: D. $10pqr$
The division is expressed as a fraction
$\frac{96\text{pqr}(3\text{p}-12)(5\text{q}-30)}{144(\text{p}-4)(\text{q}-6)}$
$\Rightarrow\frac{12\times8\text{pqr}(3\text{p}-12)(5\text{q}-30)}{12\times12(\text{p}-4)(\text{q}-6)}$
$\Rightarrow\frac{12\times8\text{pqr}\times3(\text{p}-4)\times5(\text{q}-6)}{12\times12(\text{p}-4)(\text{q}-6)}$
$\Rightarrow\frac{8\text{pqr}\times3\times5}{12}$
$\Rightarrow\frac{4\times2\text{pqr}\times3\times5}{4\times3}$
Cancel the common factors in the numerator and denominator and solve
$\Rightarrow10\text{pqr}$
View full question & answer→MCQ 341 Mark
When we factorise an expression, we write it as a $...........$ of factors.
View full question & answer→MCQ 351 Mark
Tick $(\checkmark)$ the correct answer:
$x^3 - x =\ ?$
- A
$x(x^2 - x)$
- B
$x(x - x^2)$
- C
$x(1 + x)(1 - x)$
- ✓
$x(x + 1)(x - 1)$
AnswerCorrect option: D. $x(x + 1)(x - 1)$
D. $x(x + 1)(x - 1)$
Solution:
$x^3- x$
$= x(x^2- 1)$
$= x(x - 1)(x + 1)$
View full question & answer→MCQ 361 Mark
Factorize $12ab(9a^2 - 16b^2) \div 3ab(3a + 3b)$
- A
$(3a - 4b)$
- B
$(3a + 3b)$
- C
$(3a + 4b)$
- ✓
$(3a - 4b)$
AnswerCorrect option: D. $(3a - 4b)$
D. $(3a - 4b)$
Solution:
Express the division as a fraction
$\frac{12\text{ab}(9\text{a}^2-16\text{b}^2)}{3\text{ab}(3\text{a}+4\text{b})}$
$\Rightarrow\frac{12\text{ab}((3\text{a})^3-(4\text{b}^2))}{3\text{ab}(3\text{a}+4\text{b})}$
$\Rightarrow\frac{12\text{ab}(3\text{a}+4\text{b})(3\text{a}-4\text{b})}{3\text{ab}(3\text{a}+4\text{b})}$
$\Rightarrow\frac{3\times4\text{ab}(3\text{a}+4\text{b})(3\text{a}-4\text{b})}{3\text{ab}(3\text{a}+4\text{b})}$
Cancel the common factors in the numerator and denominator
$\Rightarrow4(3\text{a}-4\text{b})$
View full question & answer→MCQ 371 Mark
The factors of $15x^2 - 26x + 8$ are:
- A
$(3x + 4)(5x + 2)$
- B
$(2x - 4)(5x + 2)$
- C
$(3x + 4)(5x - 2)$
- ✓
$(3x - 4)(5x - 2)$
AnswerCorrect option: D. $(3x - 4)(5x - 2)$
D. $(3x - 4)(5x - 2)$
View full question & answer→MCQ 381 Mark
Which of the following is equal to $x^3 – 225x.$
- A
$x(1 - 15x) (1 + 15x)$
- ✓
$x(x - 15) (x + 15)$
- C
$x(1 - 15x) (1 - 15x)$
- D
$x(1 + 15x) (1 - 15x)$
AnswerCorrect option: B. $x(x - 15) (x + 15)$
B. $x(x - 15) (x + 15)$
Solution:
Given, $x^3 - 225x$
By taking common $x,$
$\Rightarrow x(x^2 - 225)$
$\Rightarrow x(x^2 - 15^2)$
Now, using formula for $(a^2 - b^2)$
$\Rightarrow x(x - 15) (x + 15)$
As we know that $(a^2 - b^2) = (a + b) (a - b)$
Hence, $x^2 - 225x$ is equal to $x(x - 15) (x + 15).$
View full question & answer→MCQ 391 Mark
The factorisation of $z^2 - 4z - 12$ is:
- A
$(z + 6) (z + 2)$
- B
$(z - 6) (z - 2)$
- ✓
$(z - 6) (z + 2)$
- D
$(z + 6) (z - 2)$
AnswerCorrect option: C. $(z - 6) (z + 2)$
C. $(z - 6) (z + 2)$
Solution:
$= z^3 - 4z – 12$
$= z^2 - 6z + 2z - 12$
$= z(z - 6) + 2(z - 6)$
$= (z - 6) (z + 2)$
View full question & answer→MCQ 401 Mark
The common factor of $10ab, 30bc, 50ca$ is:
Answer$10ab = 2 \times 5 \times a \times b$
$30bc = 2 \times 3 \times 5 \times b \times c$
$50ca = 2 \times 5 \times 5 \times c \times a$
View full question & answer→MCQ 411 Mark
The factorisation of $12a^2b + 15ab^2$ gives:
- A
$3ab(4ab + 5)$
- ✓
$3ab(4a + 5b)$
- C
$3a(4a + 5b)$
- D
$3b(4a + 5b)$
AnswerCorrect option: B. $3ab(4a + 5b)$
B. $3ab(4a + 5b)$
Solution:
$12 a^2 b+15 a b^2 $
$12 a^2 b=3 \times 4 \times a \times a \times b $
$15 a b^2=3 \times 5 \times a \times b \times b$
The common factors are 3ab.
$12 a^2 b+15 a b^2=3 a b(4 a+5 b)$
View full question & answer→MCQ 421 Mark
The factors of $m^2 - 256$ are:
- A
$(m + 4)^2$
- B
$(m - 4)^2$
- C
$(m - 4) (m + 4)$
- ✓
AnswerD. None of the above.
Solution:
$m^2 = (m)^2$ and $256 = (16)^2$
By using the algebraic identity,
$a^2 - b^2 = (a + b) (a - b),$
we get $(m + 16) (m - 16).$
View full question & answer→MCQ 431 Mark
What are the factors of $x^2 + xy - 2xz - 2yz?$
- A
$(x - y)$ and $(x + 2z)$
- ✓
$(x + y)$ and $(x - 2z)$
- C
$(x - y)$ and $(x - 2z)$
- D
$(x + y)$ and $(x + 2z)$
AnswerCorrect option: B. $(x + y)$ and $(x - 2z)$
B. $(x + y)$ and $(x - 2z)$
View full question & answer→MCQ 441 Mark
One of the factor of $a^3 + 8b^3 - 64c^3 + 24$ abc is:
- A
$a - 2b + 4c$
- B
$a + 2b + 4c$
- ✓
$a + 2b - 4c$
- D
$a - 2b - 4c$
AnswerCorrect option: C. $a + 2b - 4c$
C. $a + 2b - 4c$
View full question & answer→MCQ 451 Mark
$39x^3 (50x^2 - 98) \div 26x^2 (5x + 7)$
- A
$3x(5x + 7)$
- B
$3x$
- C
$5x - 7$
- ✓
$3x(5x - 7)$
AnswerCorrect option: D. $3x(5x - 7)$
D. $3x(5x - 7)$
Solution:
$\frac{39\text{x}^3(50\text{x}^2-98)}{26\text{x}^2(5\text{x}+7)}$
$\Rightarrow\frac{13\times3\text{x}^3\times2(25\text{x}^2-49)}{13\times2\text{x}^2(5\text{x}+7)}$
$\Rightarrow\frac{13\times3\text{x}^2\times2((5\text{x})^2-(7)^2)}{13\times2\text{x}^2\times(5\text{x}+7)}$
$\Rightarrow\frac{13\times3\text{x}^2\times2(5\text{x}+7)(5\text{x}-7)}{2\times13\text{x}^2(5\text{x}+7)}$
Cancel the common factors
$\Rightarrow3\text{x}(5\text{x}-7)$
View full question & answer→MCQ 461 Mark
One of the factors of $\text{x}^2 + \frac{1}{\text{x}^2} + 2 - 2\text{x} - \frac{2}{\text{x}}$ is:
- A
$\text{x}-\frac{1}{\text{x}}$
- ✓
$\text{x}+\frac{1}{\text{x}}$
- C
$\text{x}+\frac{1}{\text{x}}-1$
- D
AnswerCorrect option: B. $\text{x}+\frac{1}{\text{x}}$
$\text{x}+\frac{1}{\text{x}}$
View full question & answer→MCQ 471 Mark
The factors of $\sqrt{3\text{x}^2} + 11\text{x} + 6\sqrt{3}$ are:
AnswerCorrect option: A. $(\text{x} -3\sqrt{3})(\sqrt{3\text{x}} + 2)$
$(\text{x} -3\sqrt{3})(\sqrt{3\text{x}} + 2)$
View full question & answer→MCQ 481 Mark
What is the value of $(a + 4) (a + 2)$
- A
$a^2 + 6$
- B
$a^2 + 8$
- ✓
$a^2 + 6a + 8$
- D
$a^2 + 6a + 6$
AnswerCorrect option: C. $a^2 + 6a + 8$
C. $a^2 + 6a + 8$
Solution:
$(a+4)(a+2) $
$ \Rightarrow a(a+2)+4(a+2) $
$ \Rightarrow a^2+2 a+4 a+8 $
$ \Rightarrow a^2+6 a+8$
View full question & answer→MCQ 491 Mark
Factorise: $p^4 - 81$
AnswerCorrect option: A. $(p - 3) (p + 3) (p^2 + 9)$
A. $(p - 3) (p + 3) (p^2 + 9)$
View full question & answer→MCQ 501 Mark
The factorisation of $12x + 36$ is:
- A
$12(x + 3)$
- ✓
$12(3x)$
- C
$12(3x + 1)$
- D
$x(12 + 36x)$
AnswerCorrect option: B. $12(3x)$
$= 12x + 36$
$= 12 x + 12.3$
$= 12(x + 3)$
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