A capillary tube of radius $R$ is immersed in water and water rises in it to a height $H.$ Mass of water in capillary tube is $M$. If the radius of the tube is doubled, mass of water that will rise in capillary will be:
- ✓$2M.$
- B$M.$
- C$\frac{\text{M}}{2}$
- D$4M.$
Answer: A.
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