Construct a quadrilateral $ABCD$ given that $AB = 4\ cm, BC = 3\ cm,$
$\angle\text{A}=75^\circ,$
$\angle\text{B}=80^\circ$ and $\angle\text{C}=120^\circ.$
View full solution →$\angle\text{A}=75^\circ,$
$\angle\text{B}=80^\circ$ and $\angle\text{C}=120^\circ.$