For the reaction, $2 NO _2( g ) \longrightarrow 2 NO _{( g )}+ O _{2( g )}, \quad \frac{ d \left[ NO _2\right]}{ dt } \text { is } 1.3 \times 10^{-5} mol L ^{-1} sec ^{-1} \text {. }$ What is rate of formation of $O _2$ ?
- A$1.62 \times 10^{-6} mol L ^{-1} sec ^{-1}$
- ✓$6.5 \times 10^{-6} mol L ^{-1} sec ^{-1}$
- C$1.3 \times 10^{-6} mol L ^{-1} sec ^{-1}$
- D$3.25 \times 10^{-6} mol L ^{-1} sec ^{-1}$
Answer: B.
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