Which of the following is the most basic?
- A$C _6 H _5 NH _2$
- B$\left( C _6 H _5\right)_2 NH$
- C$C _2 H _5 NH _2$
- D$\left( C _2 H _5\right)_2 NH$
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Organic Compounds Containing Nitrogen question types
51 questions across 6 question groups — pick any mix to generate a Chemistry paper with step-by-step answer keys.
51
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6
Question groups
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01
M.C.Q (1 Marks)
31 Q→021 Marks Question
4 Q→032 Marks Questions
7 Q→043 Marks Question
3 Q→055 Marks Questions
5 Q→064 Marks Questions
1 Q→Sample Questions
Organic Compounds Containing Nitrogen questions
One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
Methylamine on heating with choloroform and alcoholic KOH gives:
- A$CH _3 OH$
- B$CH _3 CN$
- C$CH _3 CHO$
- D$CH _3 NC$
- APrimary amine
- BSecondary amine
- CTertiary amine
- DQuaternary salt
Acetamide is:
- AAcidic
- BAlkaline
- CAmphoteric
- DNeutral
$CH _3 CN$ on reduction gives :
- A$CH _4$
- B$CH _3 COOH$
- C$C _2 H _5 NH _2$
- D$C _2 H _5 COOH$
Write the main product of the following :
Arrange the following compounds in increasing order of their basic strength :
$C _2 H _5 NH _2, NH _3, C _6 H _5 NH _2$
View full solution →$C _2 H _5 NH _2, NH _3, C _6 H _5 NH _2$
Arrange the following in the order of their increasing basic character :
$NH _3, C _2 H _5 NH _2,\left( C _2 H _5\right)_2 NH ,\left( C _2 H _5\right)_3 N$
View full solution →$NH _3, C _2 H _5 NH _2,\left( C _2 H _5\right)_2 NH ,\left( C _2 H _5\right)_3 N$
Explain why :
Aniline dissolves in HCl
Aniline dissolves in HCl
(a) How will you distinguish between the following pairs of compounds :
(i) Aniline and Ethanamine
(ii) Aniline and $N$-methylaniline
(b) Arrange the following compounds in decreasing order of their boiling points :
Butanol, Butanamine, Butane.
View full solution →(i) Aniline and Ethanamine
(ii) Aniline and $N$-methylaniline
(b) Arrange the following compounds in decreasing order of their boiling points :
Butanol, Butanamine, Butane.
Give the structures of $A$ and $B$ in the following sequence of reactions :
(a) $CH _3 COOH \xrightarrow[\Delta]{ NH _3} A \xrightarrow{ NaOBr } B$
(b) $C _6 H _5 NO _2 \xrightarrow{ Fe / HCl } A \xrightarrow[0^{\circ}-5^{\circ} C ]{ NaNO _2+ HCl } B$
(c) $C _6 H _5 N_2^{+} Cl ^{-} \xrightarrow[\Delta]{ CuCN } A \xrightarrow{ H _2 O / H ^{+}} B$
View full solution →(a) $CH _3 COOH \xrightarrow[\Delta]{ NH _3} A \xrightarrow{ NaOBr } B$
(b) $C _6 H _5 NO _2 \xrightarrow{ Fe / HCl } A \xrightarrow[0^{\circ}-5^{\circ} C ]{ NaNO _2+ HCl } B$
(c) $C _6 H _5 N_2^{+} Cl ^{-} \xrightarrow[\Delta]{ CuCN } A \xrightarrow{ H _2 O / H ^{+}} B$
Write the structures of compounds whose IUPAC name are as follows :
(i) $N , N$-dimethyl methanamine,
(ii) 2-Aminotoluene.
View full solution →(i) $N , N$-dimethyl methanamine,
(ii) 2-Aminotoluene.
Methylamine is more basic than aniline. Give reason.
Classify the following amines as primary, secondary and tertiary :
(iii) $\left( C _2 H _5\right)_2 CHNH _2$
(iv) $\left( C _2 H _5\right)_2 NH$
View full solution →(iii) $\left( C _2 H _5\right)_2 CHNH _2$
(iv) $\left( C _2 H _5\right)_2 NH$
Write the structures of A, B, C and D in the following reactions :
Write the following reaction :
(i) Carbylamine reaction
(ii) Diazotization reaction
(iii) Hoffmann bromamide reaction
(i) Carbylamine reaction
(ii) Diazotization reaction
(iii) Hoffmann bromamide reaction
Why is an amide more acidic than an amine?
How would you convert aniline into :
(i) Chlorobenzene
(ii) Benzoic acid
(iii) Fluorobenzene?
(i) Chlorobenzene
(ii) Benzoic acid
(iii) Fluorobenzene?
Give the structures of $A, B$ and $C$ in the following reactions :
(i) $CH _3 CH _2 I \xrightarrow{ NaCN }$$A \frac{ OH ^{-}}{\text {partial hydrolysis }} \rightarrow B$$\xrightarrow{ NaOH + Br _2} C$
(ii) $C _6 H _5 Cl \xrightarrow{ CuCN } A \xrightarrow{ H _2 O / H ^{+}} B \xrightarrow{ NH _3} C$
(iii) $CH _3 CH _2 Br \xrightarrow{ KCN } A \xrightarrow{ LiAlH _4} B \frac{ HNO _2}{0^{\circ} C } \rightarrow C$
(iv) $C _6 H _5 NO _2 \xrightarrow{ Fe / HCl } A \xrightarrow{ NaNO _2+ HCl } B$ $\xrightarrow{ H _2 O / H ^{+}} C$
(v) $CH _3 COOH \frac{ NH _3}{ Heat } \rightarrow$ A $\xrightarrow{NaOBr} B$$\xrightarrow{ NaNO _2 / HCl } C$
(vi) $C _6 H _5 NO _2 \xrightarrow{ Fe / HCl }A \frac{ HNO _2}{273 K} \rightarrow$$B \xrightarrow{ C _6 H _5 OH } C$
View full solution →(i) $CH _3 CH _2 I \xrightarrow{ NaCN }$$A \frac{ OH ^{-}}{\text {partial hydrolysis }} \rightarrow B$$\xrightarrow{ NaOH + Br _2} C$
(ii) $C _6 H _5 Cl \xrightarrow{ CuCN } A \xrightarrow{ H _2 O / H ^{+}} B \xrightarrow{ NH _3} C$
(iii) $CH _3 CH _2 Br \xrightarrow{ KCN } A \xrightarrow{ LiAlH _4} B \frac{ HNO _2}{0^{\circ} C } \rightarrow C$
(iv) $C _6 H _5 NO _2 \xrightarrow{ Fe / HCl } A \xrightarrow{ NaNO _2+ HCl } B$ $\xrightarrow{ H _2 O / H ^{+}} C$
(v) $CH _3 COOH \frac{ NH _3}{ Heat } \rightarrow$ A $\xrightarrow{NaOBr} B$$\xrightarrow{ NaNO _2 / HCl } C$
(vi) $C _6 H _5 NO _2 \xrightarrow{ Fe / HCl }A \frac{ HNO _2}{273 K} \rightarrow$$B \xrightarrow{ C _6 H _5 OH } C$
Account for the following :
(i) $p K _b$ of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Aniline does not undergo Friedel-Crafts reaction.
(v) Diazonium salts of aromatic amines are more stable than those of aliphatic amines.
View full solution →(i) $p K _b$ of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Aniline does not undergo Friedel-Crafts reaction.
(v) Diazonium salts of aromatic amines are more stable than those of aliphatic amines.
Complete the following reactions :
(i) $C _6 H _5 NH _2+ CHCl _3+$ alc. $KOH \longrightarrow$
(ii) $C _6 H _5 N_2 Cl + H _3 PO _2+ H _2 O \longrightarrow$
(iii) $C _6 H _5 NH _2+ H _2 SO _4$ (conc.) ⟶
(iv) $C _6 H _5 N_2 Cl + C _2 H _5 OH \longrightarrow$
(v) $C _6 H _5 NH _2+ Br _2(a q) \longrightarrow$
View full solution →(i) $C _6 H _5 NH _2+ CHCl _3+$ alc. $KOH \longrightarrow$
(ii) $C _6 H _5 N_2 Cl + H _3 PO _2+ H _2 O \longrightarrow$
(iii) $C _6 H _5 NH _2+ H _2 SO _4$ (conc.) ⟶
(iv) $C _6 H _5 N_2 Cl + C _2 H _5 OH \longrightarrow$
(v) $C _6 H _5 NH _2+ Br _2(a q) \longrightarrow$
How will you convert :
(i) Ethanoic acid into methanamine
(ii) Hexanenitrile into 1-aminopentane
(iii) Methanol to ethanoic acid
(iv) Ethanamine into methanamine
(i) Ethanoic acid into methanamine
(ii) Hexanenitrile into 1-aminopentane
(iii) Methanol to ethanoic acid
(iv) Ethanamine into methanamine
What is carbyl amine reaction?
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