\(r = 0.1\,cm = {10^{ - 3}}m\)

Surface tension of liquid,

\(S = 0.06\,N/m = 6 \times {10^{ - 2}}\,N/m\)

Density of liquid, \(\rho  = {10^3}\,kg/{m^3}\)

Excess pressure inside the bubble,

\({\rho _{exe}} = 1100N{m^{ - 2}}\)

Depth of bubble below the liquid surface,

\(h=?\)

As we know,

\({\rho _{Excess}} = h\rho g + \frac{{2s}}{r}\)

\( \Rightarrow 1100 = h \times {10^3} \times 9.8 + \frac{{2 \times 6 \times {{10}^{ - 2}}}}{{{{10}^{ - 3}}}}\)

\( \Rightarrow 1100 - 9800h + 120\)

\( \Rightarrow 9800h = 1100 - 120\)

\( \Rightarrow h = \frac{{980}}{{9800}} = 0.1\,m\)