Since downward force is less than limiting friction therefore block is at rest so the static force of friction will work on it.
\({F_s}\) \(=\) downward force \(=\) Weight
\( = 0.1 \times 9.8 = 0.98\,N\)
$\left[g=10 m / s ^{2} ; \sin 60^{\circ}=\frac{\sqrt{3}}{2} ; \cos 60^{\circ}=\frac{1}{2}\right]$
[ $g =9.8\, ms ^{-2}$ લો ]