c
Object is at \(2 f\). So image will also be at \(2 f\).

\(\left( I _{1}\right)\)

Image of \(I_{1}\) will be \(1\, m\) behind mirror.

i.e. \(\Rightarrow I _{2}\)

Now \(I \)\(_{2}\) will be object for lens.

\(\therefore u \Rightarrow-3 m\)

\(f \Rightarrow+0.5 m\)

\(\frac{1}{v} \Rightarrow \frac{1}{f}+\frac{1}{u}\)

\(\Rightarrow \frac{1}{+0.5}+\frac{1}{-3}\)

\(v \Rightarrow \frac{3}{5} \Rightarrow 0.6 m\)

So total distance from mirror \(\Rightarrow 2+0.6\)

\(\Rightarrow 2.6 m\) and real image