Current flowing through the wire, \(I=1\, A\)

Speed of the frame, \(\mathrm{v}=10\, \mathrm{ms}^{-1}\)

Side of square loop, \(l=10\, \mathrm{cm}\)

Distance of square frame from current carrying

wires \(x=10\, \mathrm{cm}\)

We have to find, \(e.m.f\) inducede =?

According to Biot-Savart's law

\(B = \frac{{{\mu _0}}}{{4\pi }} \cdot \frac{{Idl\sin \,\theta }}{{{x^2}}}\)

\( = \frac{{4\pi  \times {{10}^{ - 7}}}}{{4\pi }} \times \frac{{1 \times {{10}^{ - 1}}}}{{{{({{10}^{ - 1}})}^2}}}\)

\(=10^{-6}\)

Induced \(e.m.f.\) \(\mathrm{e}=\mathrm{Blv}\)

\(=10^{-6} \times 10^{-1} \times 10\)

\(=1 \,\mu v\)