d
\(r=0.1 m \quad \frac{ T }{2}=0.2 sec\)

\(B =3 \times 10^{-5} m \quad T =0.4 sec\)

At any time

\(flux \phi= BA \cos \omega t\)

\(| emf |=\left|\frac{ d \phi}{ dt }\right|=| BA \omega \sin \omega t |\)

\(( emf )_{\max }= BA \omega= BA \quad \frac{2 \pi}{ T }\)

\(=\frac{3 \times 10^{-5} \times \pi \times(0.1)^{2} \times 2 \pi}{0.4}\)

\(=\frac{6 \pi^{2}}{4} \times 10^{-6}\) \(\left(\begin{array}{c}\pi^{2}=10 \text { take }\end{array}\right)\)

\(=15 \times 10^{-6}\)

\(=15 \mu V\)