c
Strength = Normality \(\times E W\) of \(H_{2} O_{2}\) \(=1.5 N \times 1.7 g L^{-1}=25.5 g L^{-1}\)

\(\underset{68 g}{2 H_{2}} O_{2} \rightarrow 2 H_{2} O+\underset{22400 m L a t}{O_{2}}\)

\(68 g\) of \(H _{2}\) Ogives \(=22400 mL\) of \(O _{2}\) at \(STP\)

\(25.5 g H_{2} O_{2}\) gives \(=\frac{22400}{68} \times 25.5=8400 mL\) of \(O_{2}\) at \(S T P\)

\(25.5 g\) of \(H_{2} O_{2}\) is present in \(1000 m L\) of \(H _{2} O _{2}\) solution \(1000 mL\) of \(H _{2} O _{2}\) gives \(8400 mL\) of \(O _{2}\) at \(STP\)

\(1 mL\) of \(H _{2} O _{2}\) gives \(\frac{8400}{1000} mL\) of \(O _{2}\) at \(STP\)

\(=8.4 m L\) of \(O_{2}\)

Hence, volume strength of \(1.5 NH _{2} O _{2}=8.4\) volume. Or mass of \(H_{2} O_{2}\) in \(1.5 N\) solution \(=E W\) of \(H_{2} O_{2} \times 1.5 N\)

\(=17 \times 1.5=25.5 g / L\)

Hence, volume strength of \(1.5 NH _{2} O _{2}\) solution \(=\frac{22.4 \times 25.5}{68}=8.4\)