Period \((T)=2 \,s\)
\(\omega=\frac{2 \pi}{2}=\pi \,rad / s\)
When block just represent from a piston, maximum acceleration must be equal to \(g\).
\(g=-\omega^2 x\)
Acceleration is maximum when \(x=A\)
\(g=-\omega^2 A\)
or \(A=\frac{9.8}{\pi^2}\)
Maximum velocity \(=A \omega\)
\(=\frac{9.8}{\pi^2} \times \pi\)
\(=\frac{9.8}{\pi} \,m / s\)
\(=3.119 \,m / s =3.12 \,m / s\)
${x}_{1}=5 \sin \left(2 \pi {t}+\frac{\pi}{4}\right)$ અને ${x}_{2}=5 \sqrt{2}(\sin 2 \pi {t}+\cos 2 \pi {t})$
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