Using mechanical energy conservation
\(m g h=\frac{1}{2} m v^2+\frac{1}{2} l \omega^2\)
\(3(5)(10)=\frac{1}{2} m v^2+\frac{1}{2} m l^2\left(\frac{v^2}{l^2}\right)\)
\(150=\frac{3}{4} m v^2\)
\(m v^2=200\)
\(\frac{1}{2} m v^2=100 J = K \cdot E _{\cdot} \cdot \text { Translation }\)