d
In solids, Velocity of wave \(V=\sqrt{\frac{Y}{\rho}}=\sqrt{\frac{9.27 \times 10^{10}}{2.7 \times 10^{3}}}\)

\(\mathrm{v}=5.85 \times 10^{3} \mathrm{m} / \mathrm{sec}\)

since rod is clamped at middle fundamental wave shape is as follow

\(\frac{\lambda}{2}=\mathrm{L} \Rightarrow \lambda=2 \mathrm{L}\)

\(\lambda=1.2 \mathrm{m}(\because \mathrm{L}=60 \mathrm{cm}=0.6 \mathrm{m}(\mathrm{given})\)

Using \(v=f \lambda\)

\(\Rightarrow \quad f=\frac{v}{\lambda}=\frac{5.85 \times 10^{3}}{1.2}\)

\(=4.88 \times 10^{3} \mathrm{Hz}=5 \mathrm{KHz}\)