$\text { mass of carbon }=0.01 M \times \frac{60}{100}$
$\text { moles of carbon }=\frac{0.01 M }{12} \times \frac{60}{100}$
moles of $CO _2$ from combustion $=\frac{4.4}{44}=$ moles of carbon
$\frac{0.01\,M }{12} \times \frac{60}{100}=\frac{4.4}{44}$
$M =\frac{4.4}{44} \times \frac{100}{60} \times \frac{12}{0.01}=200\, gm / mol$
$3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl}$
જો $ \mathrm{PbCl}_2 $ ના $ 72 \mathrm{~m} \mathrm{~mol} \mathrm{ને}\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 $ ના $ 50 \mathrm{~m}$
$\mathrm{mol}$ સાથે મિશ્ર કરવામાં આવે તો, બનતા $\mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2$
નો જથ્થો ................... $m\ mol$ છે. (નજીકનો પૂણાંક)