A 0’5 m long metal rod PQ completes the circuit as shown in the figure. The area of the circuit is perpendicular to the magnetic field of flux density 0-15 T. If the resistance of the total circuit is 3Ω, calcularod in the direction as indicated with a constant speed ofte the force needed to move the rod in the direction as indicated with a constant speed of 2ms−1.
CBSE OUTSIDE DELHI - SET 1 2006
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Method I
$\text{E} = \text{B} $ 1 v
$\text{I} =\frac{\text{B1v}}{\text{R}} = \text{I} = 0.5\text{A}$
$\text{F} = \text{B}$ I 1
Calculation of $\text{F} = 3.75\times10^{-3}\text{N}$.
Method II
$\text{F} = \frac{\text{B}^{2}1^{2}\text{v}}{\text{R}}$
Correct substitution and calculation of $\text{F} = 3.75\times10^{-3}\text{N}$.
$\text{E} = \text{B} $ 1 v
$\text{I} =\frac{\text{B1v}}{\text{R}} = \text{I} = 0.5\text{A}$
$\text{F} = \text{B}$ I 1
Calculation of $\text{F} = 3.75\times10^{-3}\text{N}$.
Method II
$\text{F} = \frac{\text{B}^{2}1^{2}\text{v}}{\text{R}}$
Correct substitution and calculation of $\text{F} = 3.75\times10^{-3}\text{N}$.
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