ખોટું વિધાન ઓળખો.
\( = 15 - 0 = 15\,kJ\,mo{l^{ - 1}}\)
\({E_a} = (A + B) \to C = 15\,kJ\,mo{l^{ - 1}}\)
\({E_a} = (A + B) \to D = 10\,kJ\,mo{l^{ - 1}}\)
\({E_a} = C \to (A + B) = 20\,kJ\,mo{l^{ - 1}}\) (high activation enthalpy in the reaction)
\(\therefore \) Activation enthalpy to form \(C\) is \(5\,kJ\,mol^{-1}\) more than that of form \(D\).
(નજીકના પૂર્ણાંકમાં રાઉન્ડ ઑફ) $[$ ઉપયોગ કરો : $\left. R =8.31 \,J \,K ^{-1} \,mol ^{-1}\right]$