we know
\(k = \frac{{2.303}}{t}\log \frac{a}{{a - x}} = \frac{{2.303}}{{200}}\log \frac{{2.00}}{{0.15}}\)
\( = \frac{{2.303}}{{200}} \times (0.301 + 0.824) = 1.29 \times {10^{ - 2}}\,{\min ^{ - 1}}\)
$\mathrm{A}(\mathrm{g}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})+\mathrm{C}(\mathrm{g})$
$S.\ No$ સમય/s કુલ દબાણ/(atm)
$1.$ $0$ $0.1$
$2.$ $115$ $0.28$
પ્રક્રિયાનો વેગ અચળાંક _______________$\times 10^{-2} \mathrm{~s}^{-1}$ (નજીકનાં પૂનાંકમાં)
[લો; $R =8.314 \,J\, mol ^{-1}\, K ^{-1}$ In $3.555=1.268$]