A body cools from ${60^o}C$ to ${50^o}C$ in $10$ minutes. If the room temperature is ${25^o}C$ and assuming Newton's law of cooling to hold good, the temperature of the body at the end of the next $10$ minutes will be ......... $^oC$
Diffcult
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(c) $\frac{{60 - 50}}{{10}} = K\left( {\frac{{60 + 50}}{2} - 25} \right)$….$.(i)$
$\frac{{50 - \theta }}{{10}} = K\left[ {\frac{{50 + \theta }}{2} - 25} \right]$…..$(ii)$
On dividing, we get $\frac{{10}}{{50 - \theta }} = \frac{{60}}{\theta } $
$\Rightarrow \theta = {42.85^o}C$
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