A cyclic process for $1\, mole$ of an ideal gas is shown in figure in the $V-T,$ diagram. The work done in $AB, BC$ and $CA$ respectively
Medium
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(c) Process $AB$ is isochoric, $\therefore$ ${W_{AB}} = P\,\Delta V = 0$
Process $BC$ is isothermal $\therefore$ ${W_{BC}} = R{T_2}.\ln \left( {\frac{{{V_2}}}{{{V_1}}}} \right)$
Process $CA$ is isobaric
$\therefore {W_{CA}} = - \,P\Delta V$$ = - \,R\Delta T$$ = - \,R({T_1} - {T_2})$$ = R({T_2} - {T_1})$
(Negative sign is taken because of compression)
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