The process is adiabatic
$\therefore P _1 V _1^\gamma= P _2 V _2^\gamma$
Given, $\frac{ V _1}{ V _2}=\frac{2}{1}$ and $\gamma=\frac{7}{5}$ (for diatomic gas)
$\therefore \frac{ P _2}{ P _1}=(2)^{7 / 5} \quad \text { i.e., } P _2=(2)^{7 / 5} P _1$


Which of the following statement($s$) is(are) correct?
The $P-V$ diagram that best describes this cycle is
(Diagrams are schematic and not to scale)

