
Along $AB$, $P$ is constant and $\frac{1}{V}$ increases $\Longrightarrow T$ decreases
Along $BC,$ $P$ increases and $\frac{1}{V}$ remains constant $\Longrightarrow T$ increases


| Column $I$ | Column $II$ |
| $(p)$ isobaric | $(x)$ $\frac{{PV(1 - {2^{1 - \gamma }})}}{{\gamma - 1}}$ |
| $(q)$ isothermal | $(y)$ $PV$ |
| $(r)$ adiabatic | (z) $PV\,\iota n\,2$ |
The correct matching of column $I$ and column $II$ is given by

($1$) The value of $\frac{T_R}{T_0}$ is
$(A)$ $\sqrt{2}$ $(B)$ $\sqrt{3}$ $(C)$ $2$ $(D)$ $3$
($2$) The value of $\frac{Q}{R T_0}$ is
$(A)$ $4(2 \sqrt{2}+1)$ $(B)$ $4(2 \sqrt{2}-1)$ $(C)$ $(5 \sqrt{2}+1)$ $(D)$ $(5 \sqrt{2}-1)$
Give the answer or qution ($1$) and ($2$)
