$\Rightarrow \mathrm{U}=\mathrm{n}_1 \mathrm{C}_{\mathrm{V}_1} \mathrm{~T}+\mathrm{n}_2 \mathrm{C}_{\mathrm{V}_2} \mathrm{~T}$
$\Rightarrow 8 \times \frac{3 \mathrm{R}}{2} \times \mathrm{T}+6 \times \frac{5 \mathrm{R}}{2} \times \mathrm{T}$
$=27 \mathrm{RT}$
The $P-V$ diagram that best describes this cycle is
(Diagrams are schematic and not to scale)

Considering only $P-V$ work is involved, the total change in enthalpy (in Joule) for the transformation of state in the sequence $X \rightarrow Y \rightarrow Z$ is $\qquad$
[Use the given data: Molar heat capacity of the gas for the given temperature range, $C _{ v , m }=12 J K ^{-1} mol ^{-1}$ and gas constant, $R =8.3 J K ^{-1} mol ^{-1}$ ]


$I.$ Area $ABCD =$ Work done on the gas
$II.$ Area $ABCD =$ Net heat absorbed
$III.$ Change in the internal energy in cycle $= 0$
Which of these are correct