b
Let the volumes and temperatures of gas at points 1,2 and 3 are $V_1, T_1, V_2, T_2$ and $V _3, T _3$ respectively.
Given: $T_2=T_3$
Thus $\Delta U _1= nC _{ v }\left( T _2- T _1\right)$
Also $\Delta U _2= nC _{ v }\left( T _3- T _1\right)$
But $T _2= T _3 \Rightarrow \Delta U _1=\Delta U _2$
Work done by the gas in process 1, $W _1= nRT \ln \frac{ V _2}{ V _1}$
Also work done by gas in process $2, \quad W_2=n R T \ln \frac{V_3}{V_1}$
$V _3 > V _2 \Rightarrow W _2 > W _1$
From ist law: $\quad Q=\Delta U+W$
$\therefore \quad Q _{ I }=\Delta U _1+ W _1$
Also $\quad Q _2=\Delta U _2+ W _2$
$\therefore Q _2- Q _1= W _2- W _1>0 \quad\left(\because \Delta U _1=\Delta U _2\right)$
$\Rightarrow Q _2 > Q _1$