A light balloon filled with helium of density $\rho_{He}$ is tied to a light string of length $L.$ The string is tied to the ground forming an "inverted" simple pendulum (figure). If the balloon is displaced slightly from equilibrium as in figure and released, the period of the motion is. Take the density of air to be $\rho_{air}$. Assume the air applies a buoyant force on the balloon but does not otherwise affect its motion.)
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$\tau=-(B-m g) L \theta$

$\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{I}}{\mathrm{C}}}=2 \pi \sqrt{\frac{(\mathrm{B}-\mathrm{mg}) \mathrm{L}}{\mathrm{m} \theta \mathrm{L}^{2}}}$

$\mathrm{T}=2 \pi \sqrt{\frac{\rho_{\mathrm{air}} \mathrm{V}_{\mathrm{g}}-\rho_{\mathrm{He}} \mathrm{V}_{\mathrm{g}}}{\rho_{\mathrm{air}} \mathrm{V}_{\mathrm{L}}}}$

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