A liquid drop of mass $m$ and radius $r$ is falling from great height. Its velocity is proportional to ............
A$\frac{m}{r}$
B$\frac{m}{r^2}$
C$\frac{m}{r^3}$
D$\frac{m}{r^4}$
Medium
Download our app for free and get started
A$\frac{m}{r}$
a (a)
When a drop fall in air the terminal velocity of the drop is $V _0=\frac{ mg -\frac{4}{3} \pi r ^3 \rho g}{6 \pi \eta r }$ where $\rho$ is density of air $\eta$ is the viscosity of air From the above equation $V _0 \propto \frac{ m }{ r }$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A barometer kept in an elevator reads $76 \,cm$ when the elevator is accelerating upwards. The most likely pressure inside the elevator (in $cm$ of $Hg$ ) is ........
A small ball of mass $m$ and density $\rho$ is dropped in a viscous liquid of density $\rho_0$. After sometime, the ball falls with constant velocity. The viscous force on the ball is:
A air bubble rises from bottom of a lake to surface. If its radius increases by $200 \%$ and atmospheric pressure is equal to water coloumn of height $H$. then depth of lake is ..... $H$
Water is filled in a cylindrical container to a height of $3m. $ The ratio of the cross-sectional area of the orifice and the beaker is $ 0.1. $ The square of the speed of the liquid coming out from the orifice is ....... $m^2/s^2$ ($g = 10 m/s^2$)
The terminal velocity of a copper ball of radius $5\,mm$ falling through a tank of oil at room temperature is $10\,cm\,s ^{-1}$. If the viscosity of oil at room temperature is $0.9\,kg\,m ^{-1} s ^{-1}$, the viscous drag force is :
A small hole of area of cross-section $2\; \mathrm{mm}^{2}$ is present near the bottom of a fully filled open tank of height $2\; \mathrm{m} .$ Taking $\mathrm{g}=10 \;\mathrm{m} / \mathrm{s}^{2},$ the rate of flow of water through the open hole would be nearly ......... $\times 10^{-6} \;m^{3} /s$
Two tubes of radii $r_1$ and $r_2$, and lengths $l_1$ and $l_2$, respectively, are connected in series and a liquid flows through each of them in streamline conditions. $P_1$ and $P_2$ are pressure differences across the two tubes. If $P_2$ is $4P_1$ and $l_2$ is $ \frac{l_1}{4}$ , then the radius $r_2$ will be equal to