A metal block of base area $0.20\,m ^2$ is placed on a table, as shown in figure. A liquid film of thickness $0.25\,mm$ is inserted between the block and the table. The block is pushed by a horizontal force of $0.1\,N$ and moves with a constant speed. If the viscosity of the liquid is $5.0 \times 10^{-3} \;Pa-s$, the speed of block is $.........\times 10^{-3}\,m / s$
JEE MAIN 2023, Medium
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$| F |=\eta A \frac{\Delta v }{\Delta h }: 0.1=5 \times 10^{-3} \times 0.2 \times \frac{ v }{.25 \times 10^{-3}}$
$v =0.025\,m / s \text { or } v =25 \times 10^{-3}\,m / s$
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