A monoatomic gas performs a work of $\frac{Q}{4}$ where $Q$ is the heat supplied to it. The molar heat capaticy of the gas will be $R$ during this transformation. Where $R$ is the gas constant.
A$9$
B$25$
C$2$
D$8$
JEE MAIN 2022, Medium
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C$2$
c $\Delta Q =\Delta E + WD \Rightarrow Q =\Delta E +\frac{ Q }{4}$
$\Rightarrow n \frac{3\, R }{2} \Delta T =\Delta E =\frac{3\, Q }{4}$
$\therefore n \Delta T =\frac{ Q }{2\, R }$
$\therefore C =2$
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