A moving coil galvanometer is converted into an ammeter reading u… - Vidyadip

Question

A moving coil galvanometer is converted into an ammeter reading upto $0.03\,A$ by connecting a shunt of resistance $4r$ across it and into an ammeter reading upto $0.06\,A$ when a shunt of resistance $r$ is connected across it. What is the maximum current which can be sent through this galvanometer if no shunt is used ............... $A$

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Answer

$\frac{{{i_g}}}{i} = \frac{S}{{G + S}} \Rightarrow {i_g}G = (i - {i_g})S$

$\therefore $ ${i_g}G = (0.03 - {i_g})4r$ ..... $(i)$

and ${i_g}G = (0.06 - {i_g})r$ ..... $(ii)$

From $(i)$ and $(ii)$

$0.12 - 4{i_g} = 0.06 - {i_g}$ $ \Rightarrow {i_g} = 0.02A$.

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