A network of four 10 $\mu$F capacitors is connected to a 500 V supply as shown in the figure. Determine the
  1. equivalent capacitance of the network and
  2. charge on each capacitor
CBSE OUTSIDE DELHI - SET 2 GUHAWATI 2015
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  1. Equivalent capacitance $(\text{C}_{n}) = \frac{\text{C}}{3} + \text{C}$
$ = \frac{4\text{C}}{3} = \frac{40}{3}\mu\text{F}$
  1. $\text{Charge on } \text{C}_{4}, \text{q}_{4} = \text{C}_{4}\times\text{V}=10\times500 \mu\text{C}$
$ = 5\times10^{-3}\text{C} = 5 \text{mC}$

$\text{Charge on } \text{C}_ {1},\text{C}_{2},\text{C}_{3}\text{ is same and is equal to } \frac{\text{C}}{3}\times\text{V}$

$ = \frac{5}{3}\times10^{-3}\text{C}$

$ = 1.67\text{mC}$.
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