A short electric dipole has a dipole moment of $16 \times 10^{-9}\, Cm .$ The electric potential due to the dipole at a point at a distance of $0.6\, m$ from the centre of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is $.........V$
$\left(\frac{1}{4 \pi \epsilon_{0}}=9 \times 10^{9} Nm ^{2} / C ^{2}\right)$
NEET 2020, Medium
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$V=\frac{k P \cos \theta}{r^{2}}=\frac{9 \times 10^{9} \times 16 \times 10^{-9}}{(0.6)^{2}} \times \frac{1}{2}$
$V=200\, V$
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