A small body of mass $0.10\, kg$ is executing $S.H.M.$ of amplitude $1.0 \,m$ and period $0.20\, sec$. The maximum force acting on it is.... $N$
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(a) Maximum acceleration
${A_{\max }} = a{\omega ^2}$

$= \frac{{a \times 4{\pi ^2}}}{{{T^2}}}$

$ = \frac{{1 \times 4 \times {{(3.14)}^2}}}{{0.2 \times 0.2}}$

${F_{\max }} = m \times {A_{\max }}$

$= \frac{{0.1 \times 4 \times {{(3.14)}^2}}}{{0.2 \times 0.2}}$

$= 98.596\;N$

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