a
Force on wire $\mathrm{ACD}=$ Force on $\mathrm{AD}=$ Force on $AED$
All these forces are acting along $EC$.
Net force on the loop $=3\left(\mathrm{F}_{\mathrm{AD}}\right)$
or $\mathrm{F}_{\mathrm{net}}=3(\mathrm{i})(\mathrm{AD})(\mathrm{B})=(3)(3.0)(2 \sqrt{2})$
$(2.0)\, \mathrm{N}=36 \sqrt{2} \,\mathrm{N}$