A thermodynamic system goes from states $(i)\,\,{P_1}, V$ to $2{P_1}, V\, (ii)\, P, V$ to $P, 2V.$ Then work done in the two cases is
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(b) $(i)$ Case $ \to $Volume = constant $ \Rightarrow \int_{}^{} {PdV} = 0$
$(ii)$ Case$ \to P =$ constant $ \Rightarrow \int_{\,{V_1}}^{\,2{V_1}} {PdV} = P\int_{\,{V_1}}^{\,2{V_1}} {dV = P{V_1}} $
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