so effective resistance is \(12\) \(\Omega\)
which is in parallel with \(3\) \(\Omega\),
so \(\frac{1}{R} = \frac{1}{3} + \frac{1}{{12}} = \frac{{15}}{{36}}\)
\( \Rightarrow \) \(R = \frac{{36}}{{15}}\)
\(I = \frac{V}{R} = \frac{{4.8 \times 15}}{{36}} = 2\,A\)
જયાં $i$ એ પોટેન્શિયોમિટર તારનો પ્રવાહ છે.